SOAL
  1. Tentukan suku ke 6,10,dan 20 dari deret berikut 7,12,17,22,27 !
  2. Tentukan jumlah deret ke 6,10,20 dari deret berikut 2,4,6,8,10 !
  3. Tentukan suku ke 5 dan 10 , jika suku pertama 200 dan bedanya 25 !

JAWAB
1.a
Sn = a + (n-1)b
S6 = 7 + (6-1)5
S6 = 7 + 5.5
S6 = 7 + 25
S6 = 32

1.b
S10 = 7 + (10-1)5
S10 = 7 + 9.5
S10 = 52

1.c
S20 = 7 + (20-1)5
S20 = 7 + 19.5
S10 = 102

2.a
J6 = n/2 ( 2a + (n - 1) b)
J6 = 6/2 ( 2.2 + (6 – 1) 2)
J6 = 3 ( 4 + 5.2 )
J6 = 3 ( 4 + 10 )
J6 = 3. 14
J6 = 42

2.b
J10 = 10/2 (2.2+ (10-1)2)
J10 = 5 (4 + 9. 2)
J10 = 5 (4 + 18)
J10 = 5. 22
J10 = 110

2.c
J20 = 20/2 ( 2.2 + (20-1)2)
J20 = 10 (4+ 19.2)
J20 = 10 (4 + 38)
J20 = 10. 42
J20= 420

Dik :
a= 200
b= 25

3.a
Sn = a + (n-1)b
S5 = 200 + (5-1)25
S5 = 200 + 4. 25
S5 = 200 + 100
S5 = 300

3.b
Sn = a + (n-1)b
S10 = 200 + (10-1)25
S10 = 200 + 9. 25
S10 = 200 + 225
S10 = 425


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